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Make remove_list_redundancies keep last-most occurance of an element rather than the first occurance

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Grant Sanderson 2018-02-06 12:23:01 -08:00
parent 4f322f3137
commit 3f445cb14e
1 changed files with 8 additions and 6 deletions
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14
helpers.py
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@ -199,14 +199,16 @@ def bezier(points):
def remove_list_redundancies(l): def remove_list_redundancies(l):
""" """
Used instead of list(set(l)) to maintain order Used instead of list(set(l)) to maintain order
Keeps the last occurance of each element
""" """
result = [] reversed_result = []
used = set() used = set()
for x in l: for x in reversed(l):
if not x in used: if not x in used:
result.append(x) reversed_result.append(x)
used.add(x) used.add(x)
return result reversed_result.reverse()
return reversed_result
def list_update(l1, l2): def list_update(l1, l2):
""" """
@ -649,8 +651,8 @@ def angle_between_vectors(v1, v2):
return np.arccos(np.dot(v1,v2)/(l1*l2)) return np.arccos(np.dot(v1,v2)/(l1*l2))
def project_along_vector(point, vector): def project_along_vector(point, vector):
matrix = np.eye(3) - np.outer(vector,vector) matrix = np.identity(3) - np.outer(vector, vector)
return np.dot(point,matrix.T) return np.dot(point, matrix.T)
def concatenate_lists(*list_of_lists): def concatenate_lists(*list_of_lists):
return [item for l in list_of_lists for item in l] return [item for l in list_of_lists for item in l]